Reduce the following fraction: -32abc/64a^2bc^2a. - 1/2ac^2b.- 16ac/^2c.1ac^2/2d. - 32/6ac^2
Accepted Solution
A:
Answer:[tex]-\dfrac{1}{2ac}[/tex]Step-by-step explanation:Given: [tex]\dfrac{-32abc}{64a^2bc^2}[/tex]Reduce this fraction.Work with numbers and different letters separately:1. Numbers:[tex]\dfrac{-32}{64}=-\dfrac{32}{32\cdot 2}=-\dfrac{1}{2}[/tex]2. Letter a:[tex]\dfrac{a}{a^2}=\dfrac{a}{a\cdot a}=\dfrac{1}{a}[/tex]3. Letter b:[tex]\dfrac{b}b}=1[/tex]4. Letter c:[tex]\dfrac{c}{c^2}=\dfrac{c}{c\cdot c}=\dfrac{1}{c}[/tex]Hence,[tex]\dfrac{-32abc}{64a^2bc^2}=-\dfrac{1}{2}\cdot \dfrac{1}{a}\cdot \dfrac{1}{c}=-\dfrac{1}{2ac}[/tex]