MATH SOLVE

2 months ago

Q:
# Please help with this math problem This figure is made up of a rectangle and parallelogram. What is the area of this figure? Enter your answer. Do not round any side lengths. Coordinate plane with axes labeled x and y. A closed figure is formed by a parallelogram and rectangle. The vertices are (-6, -1), (2, 1), (2, 7), (3, 3), (3,-3) and (-5,5).

Accepted Solution

A:

First, draw a line connecting (3, -3) and (2,1), to enclose the rectangle.

Find the dimensions of this rectangle and then calculate the area.

Length of rectangle: sqrt(64+4) = sqrt(68) = sqrt(17)sqrt(4)

Width of rectangle: sqrt(16+1) = sqrt(17)

Area of rectangle: sqrt(17)sqrt(4)sqrt(17) = 17(2) = 34

Width of parallelogram: 1

Length of parallelogram: 6

Area of parallelogram: 6

Total area of figure: 34 + 6 = 40 square units (answer)

Find the dimensions of this rectangle and then calculate the area.

Length of rectangle: sqrt(64+4) = sqrt(68) = sqrt(17)sqrt(4)

Width of rectangle: sqrt(16+1) = sqrt(17)

Area of rectangle: sqrt(17)sqrt(4)sqrt(17) = 17(2) = 34

Width of parallelogram: 1

Length of parallelogram: 6

Area of parallelogram: 6

Total area of figure: 34 + 6 = 40 square units (answer)